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x^2+100x-300000=0
a = 1; b = 100; c = -300000;
Δ = b2-4ac
Δ = 1002-4·1·(-300000)
Δ = 1210000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1210000}=1100$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-1100}{2*1}=\frac{-1200}{2} =-600 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+1100}{2*1}=\frac{1000}{2} =500 $
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